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Given an array of integers, calculate the ratios of its elements that are positive, negative, and zero. Print the decimal value of each fraction on a new line with places after the decimal.
Note: This challenge introduces precision problems. The test cases are scaled to six decimal places, though answers with absolute error of up to are acceptable.
Example
There are elements, two positive, two negative and one zero. Their ratios are , and . Results are printed as:
0.400000
0.400000
0.200000
Function Description
Complete the plusMinus function in the editor below.
plusMinus has the following parameter(s):
- int arr[n]: an array of integers
Print
Print the ratios of positive, negative and zero values in the array. Each value should be printed on a separate line with digits after the decimal. The function should not return a value.
Input Format
The first line contains an integer, , the size of the array.
The second line contains space-separated integers that describe .
Constraints
Output Format
Print the following lines, each to decimals:
- proportion of positive values
- proportion of negative values
- proportion of zeros
Sample Input
STDIN Function
----- --------
6 arr[] size n = 6
-4 3 -9 0 4 1 arr = [-4, 3, -9, 0, 4, 1]
Sample Output
0.500000
0.333333
0.166667
-----------------------------------------xxxxxxxx-----------------------------
Java Code
2021
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;
class Result {
/*
* Complete the 'plusMinus' function below.
*
* The function accepts INTEGER_ARRAY arr as parameter.
*/
public static void plusMinus(List<Integer> arr) {
// porpostion of positive numbers
// porpostion of negative numbers
// zeros
int positive_numbers=0;
int negative_numbers=0;
int zero_numbers=0;
int total_numbers=arr.size();
for(Integer var: arr) {
if(var ==0) {
zero_numbers+=1;
}
else if(var <0) {
negative_numbers+=1;
}else {
positive_numbers+=1;
}
}
double positive=(double)positive_numbers/total_numbers;
double negative=(double)negative_numbers/total_numbers;
double zeros=(double)zero_numbers/total_numbers;
System.out.println(String.format("%.6f",positive));
System.out.println(String.format("%.6f",negative));
System.out.println(String.format("%.6f",zeros));
}
}
public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(bufferedReader.readLine().trim());
List<Integer> arr = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
.map(Integer::parseInt)
.collect(toList());
Result.plusMinus(arr);
bufferedReader.close();
}
}
About Author
Если вам необходим ремонт холодильника Гаггенау в Москве, множество сервисных центров предлагают квалифицированную помощь. Профессионалы осуществляют ремонт на дому, гарантируя быстрое устранение неисправностей и восстановление функциональности устройства. Используются исключительно оригинальные запчасти, что обеспечивает долговечность и надежность ремонта, а также продлевает срок службы техники.
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